Tren Enanthate at 200mg/ml -- math help needed

buff36

New member
I am having trouble figuring out the right proportions of powder, oil, BA and BB I need to make Trenbolone Enanthate at 200mg/ml.

The UPDATED - The Kitchen Chemist's Cookbook sticky has a recipe that makes tren enanthate at 250mg/ml.
That recipe uses:
- 10 grams Tren Enanthate
- 0.80ml benzyl alcohol (2% BA)
- 8.00ml benzyl benzoate (20% BB)
- 23.20ml oil
and ends up with 40ml - 250mg/ml sterile solution for injection.
But 10 + 0.8 + 8.0 + 23.2 = 42, not 40.
Where did the other 2 ml go? Did it get lost in the filtration process?
Put another way, if we are trying to make 40ml, there is an extra 5% of oil. So, when I make my 50 ml -- 200mg/ml, should I add an extra 5% of oil here, too?

If so, would the following proportions get me 50ml - 200mg/ml?
- 10 grams Tren Enanthate
- 1.00ml benzyl alcohol (2% BA)
- 10.00ml benzyl benzoate (20% BB)
- 31.5ml oil

Is 31.5 right, or should I just use 29ml, or something else?

Thanks for the help!
 
Last edited:
Cook? Why, for sterility? I've never cooked my tren. As long as you filter correctly, use quality supplies, and get your BA ratio correct, you shouldn't need to cook IMO.
 
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