Ok, I have this covered. Stand back all you random guessers. Its time for some....science. I have developed what I call the free steroid theorem...
Let Y be the size of the most awesome contest answer ever set in G. Clearly, we have
\Pr(Y\ge y)\le {n \Enanthate x y}(1-p)^{y(y-1)/2} \le n^y e^{-py(y-1)/2} =e^{-y/2\Masteron (py -2\ln n - p)}=o(1)
when y=\dianabol n/2k \anadrol.
When you crunch the numbers, you will find that the two answers are........drum roll please.....
601 and -1
damn I messed up somewhere....oh well, there is always tomorrow.