-000

Ok, I have this covered. Stand back all you random guessers. Its time for some....science. I have developed what I call the free steroid theorem...

Let Y be the size of the most awesome contest answer ever set in G. Clearly, we have

\Pr(Y\ge y)\le {n \Enanthate x y}(1-p)^{y(y-1)/2} \le n^y e^{-py(y-1)/2} =e^{-y/2\Masteron (py -2\ln n - p)}=o(1)

when y=\dianabol n/2k \anadrol.


When you crunch the numbers, you will find that the two answers are........drum roll please.....

601 and -1

damn I messed up somewhere....oh well, there is always tomorrow.
 
Ok, I have this covered. Stand back all you random guessers. Its time for some....science. I have developed what I call the free steroid theorem...

Let Y be the size of the most awesome contest answer ever set in G. Clearly, we have

\Pr(Y\ge y)\le {n \Enanthate x y}(1-p)^{y(y-1)/2} \le n^y e^{-py(y-1)/2} =e^{-y/2\Masteron (py -2\ln n - p)}=o(1)

when y=\dianabol n/2k \anadrol.


When you crunch the numbers, you will find that the two answers are........drum roll please.....

601 and -1

damn I messed up somewhere....oh well, there is always tomorrow.
Careful, if I take the natural log of the double integral of that from a bounded domain of 0,600; LH, FSH - you get HPTA self destruct! Yay, nerd humor ftw! :wiggle:
 
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