V valody New member Feb 18, 2010 #1 I have two question: *The question is cc=ml. *If I add 5ml of bacteriostatic water to HCG will I have 5000iu?
I have two question: *The question is cc=ml. *If I add 5ml of bacteriostatic water to HCG will I have 5000iu?
StoneColdNTO Administrator Feb 18, 2010 #2 Yes....one cc = one ml Second part of your question makes no sense
V valody New member Feb 18, 2010 #3 Im looking at HCG 5000iu vial, its in powder form. I been told that if I add 5ml of bacteriostatic water I will have 5000ml.
Im looking at HCG 5000iu vial, its in powder form. I been told that if I add 5ml of bacteriostatic water I will have 5000ml.
StoneColdNTO Administrator Feb 18, 2010 #4 valody said: Im looking at HCG 5000iu vial, its in powder form. I been told that if I add 5ml of bacteriostatic water I will have 5000ml. Click to expand... No you will not have 5000ml......lol If you add 5ml water to 5000iu, you will have a solution of 1000iu/ml
valody said: Im looking at HCG 5000iu vial, its in powder form. I been told that if I add 5ml of bacteriostatic water I will have 5000ml. Click to expand... No you will not have 5000ml......lol If you add 5ml water to 5000iu, you will have a solution of 1000iu/ml
scotimusprime Setting NEWB Gun to KILL Feb 18, 2010 #5 ya u will still have only 5mls but each ml will contain 1000iu like stone said
C cyto33 New member Feb 18, 2010 #6 5000iu divided by # X will give you Xiu 5000iu/10 = 500iu-p-ml 5000iu/20 = 250iu-p-ml see the way this works.
5000iu divided by # X will give you Xiu 5000iu/10 = 500iu-p-ml 5000iu/20 = 250iu-p-ml see the way this works.
scotimusprime Setting NEWB Gun to KILL Feb 18, 2010 #7 cyto please tell me you dont know those blondes. lol
V valody New member Feb 18, 2010 #9 StoneColdNTO said: No you will not have 5000ml......lol If you add 5ml water to 5000iu, you will have a solution of 1000iu/ml Click to expand... Thanks
StoneColdNTO said: No you will not have 5000ml......lol If you add 5ml water to 5000iu, you will have a solution of 1000iu/ml Click to expand... Thanks